Multiplicatively closed set

From Infogalactic: the planetary knowledge core
(Redirected from Multiplicative subset)
Jump to: navigation, search

In abstract algebra, a multiplicatively closed set (or multiplicative set) is a subset S of a ring R such that the following two conditions hold:[1][2]

  • 1 \in S.
  • For all x and y in S, the product xy is in S.

In other words, S is closed under taking finite products, including the empty product 1.[3] Equivalently, a multiplicative set is a submonoid of the multiplicative monoid of a ring.

Multiplicative sets are important especially in commutative algebra, where they are used to build localizations of commutative rings.

A subset S of a ring R is called saturated if it is closed under taking divisors: i.e., whenever a product xy is in S, the elements x and y are in S too.

Examples

Common examples of multiplicative sets include:

Properties

  • An ideal P of a commutative ring R is prime if and only if its complement R\P is multiplicatively closed.
  • A subset S is both saturated and multiplicatively closed if and only if S is the complement of a union of prime ideals.[4] In particular, the complement of a prime ideal is both saturated and multiplicatively closed.
  • The intersection of a family of multiplicative sets is a multiplicative set.
  • The intersection of a family of saturated sets is saturated.

See also

Notes

<templatestyles src="Reflist/styles.css" />

Cite error: Invalid <references> tag; parameter "group" is allowed only.

Use <references />, or <references group="..." />

References

  • M. F. Atiyah and I. G. Macdonald, Introduction to commutative algebra, Addison-Wesley, 1969.
  • David Eisenbud, Commutative algebra with a view toward algebraic geometry, Springer, 1995.
  • Lua error in package.lua at line 80: module 'strict' not found.
  • Serge Lang, Algebra 3rd ed., Springer, 2002.
    • Atiyah and Macdonald, p. 36.
    • Lang, p. 107.
    • Eisenbud, p. 59.
    • Kaplansky, p. 2, Theorem 2.